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5 votes
In the U

f(x) =
f'(x) =
xsinx COSX
oxsinx - cosx + (xsinx) - D[cosx)
+
D[x sinx] =
J₁
11
=
o[f(x). g(x)] = f'(x) g(x) + f(x
$6
D[sinx]
D[x]. sinx + x.
. Sinx
Sinx + x CUSX
1
sinx +X COSX
x COSY
£²
(x) = (sinx +xcosx) COSX + (xsinx)(-sinx)
f'(x) =
2
X Sin x

In the U f(x) = f'(x) = xsinx COSX oxsinx - cosx + (xsinx) - D[cosx) + D[x sinx] = J-example-1

1 Answer

3 votes
Refer to the photo taken.
In the U f(x) = f'(x) = xsinx COSX oxsinx - cosx + (xsinx) - D[cosx) + D[x sinx] = J-example-1
User Jan Galtowski
by
3.3k points