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Abc is right angled triangle at A which tan B=1 then tan C-sin B cos C=...

User Shrikey
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1 Answer

4 votes

Answer:

1/2

Explanation:

Given right triangle ABC with right angle A and tan(B) = 1, you want the value of the expression tan(C) -sin(B)cos(C).

Angles

Angle A is given as 90°.

Angle B is found from ...

tan(B) = 1 ⇒ B = arctan(1) = 45°

Angle C is its complement:

C = 90° -B = 45°

Trig functions

The relevant trig functions are ...

tan(C) = tan(45°) = 1

sin(B) = sin(45°) = 1/√2

cos(C) = cos(45°) = 1/√2

Expression

Then the value of the expression is ...

tan(C) -sin(B)cos(C)

= 1 -(1/√2)(1/√2) = 1 -1/2

= 1/2

User Rluta
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