Question

200 mL of water is added to 700 mL of a 3-M NaCl solution. What is the concentration of the diluted solution?

Answer 1

The concentration of the diluted NaCl solution is 10.5 M.

Step-by-step explanation:

To determine the concentration of the diluted solution, we can use the equation:

C1V1 = C2V2

Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

In this case, we have:

C1 = 3 M (from the 700 mL of 3-M NaCl solution)

V1 = 700 mL

C2 = ? (what we want to find)

V2 = 200 mL (the amount of water added)

Plugging these values into the equation, we have:

3 M * 700 mL = C2 * 200 mL

C2 = (3 M * 700 mL) / 200 mL

C2 = 10.5 M

So, the concentration of the diluted NaCl solution is 10.5 M.

Answer 2

2.3 M

Step-by-step explanation:

First we calculate the final volume of the solution:

• Final Volume = 200 mL + 700 mL

• Final Volume = 900 mL

With the final volume we can use a dilution factor to calculate the concentration of the diluted solution:

• Original Concentration * Initial Volume / Final Volume = Final Concentration

• 3 M * 700 mL / 900 mL = 2.3 M