Question

Q3. An object has a weight of 70 N. How high can the object be lifted, if 210 J of work is done on it?​

Answer 1

The height will be 3

Step-by-step explanation:

force(f) = 70N

work(w) = 210 J

distance(d) = ?

w = f × d

210 = 70 × d

210 = 70d

divide both sides by (70) to get d

`(210)/(70) = (70d)/(70)`

d = 3

i hope this helps

Answer 2

Important Formulas:

`w=Fd`

work(measured in joules) = force(measured in newtons) * distance(measured in meters)

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Given:

`F=70N`

`w=210J`

`d=?`

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Rearrange formula to make distance the subject:

`W=Fd`

`(W)/(F) =(Fd)/(F)`

`d=(W)/(F)`

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`d=(210)/(70)`

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`\fbox{d = 3 meters}`