Question

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT. Find The area of the rhombus.

The area of the rhombus is_______

Answer 1

Given:

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• Diagonal 1 = 19 ft

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• Diagonal 2 = 29 ft

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To find:

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• Area of figure (rhombus)

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Solution:-

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Ad we know Area of rhombus has two Formulas:-

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First :-

Area = (Diagonal 1 × Diagonal 2)/2

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Second:-

Area = B × h

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As we know in this case base and height aren't given, so we will use first formula to find rhombus.

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We know:-

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`\dashrightarrow \sf{}Area \: of \: rhombus = (diagonal_1 * diagonal_2)/(2) \\`

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`\dashrightarrow \sf{}Area \: of \: rhombus = (19 * 29)/(2) \\`

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`\dashrightarrow \sf{}Area \: of \: rhombus = (551)/(2) \\`

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`\dashrightarrow \bf{}Area \: of \: rhombus = 275.5 \: {ft}^(2) \\`

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know more :-

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`\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length* Breadth \\\\ \star\sf Triangle=(1)/(2)* Base* Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\frac {1}{2}* d_1* d_2 \\\\ \star\sf Rhombus =\:\frac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base* Height\\\\ \star\sf Trapezium =\frac {1}{2}(a+b)* Height \\ \\ \star\sf Equilateral\:Triangle=\frac {√(3)}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}`