422,853 views
43 votes
43 votes
What are my zeros (x^2 - 8x + 1)?

User Roshnal
by
2.6k points

1 Answer

24 votes
24 votes

Answer:

x= 7.87298334621 x=.12701665379

Explanation:

This is in standard form so we have to factor this into

x^2-8x + 16 + 1 = 16

(x-4)^2 = 15

(x-4) =
image

x-4= ± 3.87298334621

x-4 = 3.87298334621 x-4= -3.87298334621

x= 7.87298334621 x=.12701665379

User Chris Oldwood
by
2.7k points
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