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How many different 9-letter strings can be made by rearranging the characters in the word WISCONSIN?

a. 9^6
b. 9! / 8
c. C(9,6)
d. 9!
e. 9! / 6

User Arghtype
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1 Answer

5 votes

Answer:

d. 9!

To solve this problem, you can use the permutation formula, which is given by the following:


$$P_(n)^(r) = (n!)/((n - r)!)$$

In this formula,
$n$ is the total number of items, and
$r$ is the number of items being chosen at a time.

In this case, we have a total of 9 letters in the word WISCONSIN, and we want to rearrange them to form 9-letter strings. Therefore, we can use the permutation formula as follows:


$$P_(9)^(9) = (9!)/((9 - 9)!) = (9!)/(0!) = 9! = \boxed{362,!880}$$

This means that there are 362,880 different 9-letter strings that can be made by rearranging the characters in the word WISCONSIN.

User Benoit Pasquier
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