Question

Calculate the molality of 6.0 M H2SO4

Solution. The density of the solution is 1.34g/mL.
A. 4.48 m
B. 10.2 m
C. 8.10 m
D. 8.43 m
E. 7.98 m

Answer 1

A

Step-by-step explanation:

To calculate the molality of a solution, you need to know the mass of the solute (in this case, H2SO4) and the mass of the solvent (in this case, water). To find the mass of the solvent, you can use the density of the solution and the volume of the solvent:

Density = Mass / Volume

Rearranging the equation and solving for mass:

Mass = Density * Volume

You can then use the mass of the solvent and the molarity of the solution to calculate the molality:

Molality = (Moles of solute) / (Mass of solvent in kilograms)

For a 6.0 M solution of H2SO4, the moles of solute can be calculated by multiplying the molarity by the volume of the solution:

Moles of solute = Molarity * Volume = 6.0 M * 1.00 L = 6.0 moles

If the density of the solution is 1.34 g/mL and the volume of the solution is 1.00 L, the mass of the solvent can be calculated as follows:

Mass of solvent = Density * Volume = 1.34 g/mL * 1.00 L = 1.34 grams

To convert the mass of the solvent to kilograms, you can divide the mass by 1000:

Mass of solvent in kilograms = 1.34 grams / 1000 = 0.00134