Question

suppose that a box contains 6 cameras and that 5 of them are defective. a sample of 2 cameras is selected at random ( without replacement). define the random variable x as the number of defective cameras in the sample. write the probability distribution for x .write your answer in fraction form or round to 3 decimal places.

Answer 1

If x is the number of defective cameras in the 2-size sample, that means that:

P(x = 0) = 0 (since there are no 2 cameras that can be selected without replacement that are not defective)

P(x = 1) = 5/15 = 1/3 (since there are 15 total ways to select a distinct sample and only 5 of these would have the non-defective one in them)

P(x = 2) = 10/15 = 2/3 (since there are 15 total ways to select a distinct sample and 10 of these would NOT have the non-defective one in them)