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5 votes
In a board of directors composed of 14 people, how many different ways can one chief

executive officer, one director, and one treasurer be selected?

User Thilanka
by
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1 Answer

5 votes

Answer:

2184

Explanation:

This question involves permutations. We can solve it using the formula


(n!)/((n-r)!)

where n=14 (because we are choosing from 14 people)

and r=3 (because we are choosing 3 people)

and we are using the permutation formula because the order or placement in which these 3 people are choosing matters (having a person 1 being a director is different from having person 1 being a chief executive officer)

14!/(14-3)!

= 14!/11!

= 14 x 13 x 12

= 2184