Question

Find the equation of the straight line that has a slope of 4 and passes through the point (-1, -6)

Answer 1

`y - (-6) = 4(x - (-1))` or
`y = 4x - 2`

Explanation:

We can use point slope form:
`y - y_(1) = m(x - x_(1))`, where
`(x_1, y_1)` is a point on the line and
`m` is the slope.

We plug in (-1, -6) and 4 to get: which simplifies to
`y + 6 = 4(x + 1)`

If we want to express this in the form y = mx + b, we have to do a little rearranging.
`y + 6 = 4(x + 1)` becomes
`y + 6 = 4x + 4` and then we subtract 6 from both sides to get:
`y = 4x - 2`

Answer 2

y = 4x - 2

Explanation:

y = 4x + b

-6 = 4(-1) + b

-6 = -4 + b

b = -2

y = 4x - 2