Explanation:
Solution,
∠IDJ = 70° ( being alternate angle in AB || CD )
∠ IDJ + x = 180° ( being co-interior angle in EF || GH )
or , 70° + x = 180°
or , x = 180° - 70°
x = 110°
Again,
∠BLH = ∠CKG ( Being alternate angle in AB || CD )
y = 110°
Finally ,
z + y = 180° ( Being adjacent supplementary angle )
or , z + 110° = 180°
z = 70°
Thus , x = 110 ° , y = 110 ° and z = 70°