Question

You need to write a menu driven program. The program allows a user to enter five numbers and then asks the user to select a choice from a menu. The menu should offer the following four options – 1. Display the smallest number entered 2. Display the largest number entered 3. Display the sum of the five numbers entered 4. Display the average of the five numbers entered

Answer 1

In Python:

nums = []

for i in range(5):

num = int(input("Num: "))

nums.append(num)

print("1 - Smallest")

print("2 - Largest")

print("3 - Sum")

print("4 - Average")

menu = int(input("Select menu: "))

if menu == 1:

print("Smallest: ",min(nums))

elif menu == 2:

print("Largest: ",max(nums))

elif menu == 3:

isum = 0

for i in range(5):

isum+=nums[i]

print("Sum: ",isum)

elif menu == 4:

isum = 0

for i in range(5):

isum+=nums[i]

print("Average: ",isum/5)

else:

print("Invalid Menu Selected")

Step-by-step explanation:

This program uses a list to get inputs for the 5 numbers

Here, the list is initialized

nums = []

This iterates from 1 to 5

for i in range(5):

This gets input for the 5 numbers

num = int(input("Num: "))

This appends each number to the list

nums.append(num)

The next 4 lines represents the menu

print("1 - Smallest")

print("2 - Largest")

print("3 - Sum")

print("4 - Average")

This prompts the user for menu

menu = int(input("Select menu: "))

If menu is 1, print the smallest

if menu == 1:

print("Smallest: ",min(nums))

If menu is 2, print the largest

elif menu == 2:

print("Largest: ",max(nums))

If menu is 3, calculate and print the sum of all inputs

elif menu == 3:

isum = 0

for i in range(5):

isum+=nums[i]

print("Sum: ",isum)

If menu is 4, calculate and print the average of all inputs

elif menu == 4:

isum = 0

for i in range(5):

isum+=nums[i]

print("Average: ",isum/5)

If menu is not 1 to 4, then print invalid menu

else:

print("Invalid Menu Selected")