Question

Croissants cost 85p each and pain au chocolate cost 95p each. Didier buys 22 pastries and spends a total of £20. How many croissants and how many pain au chocolat did he buy?

Answer 1

croissants: 10 pain au chocolat: 12

Explanation:

85c + 95p = 2000

c + p = 22

85c + 95p = 2000

-

85c + 85p = 1870

10p = 120

p = 12

c + p = 22

c + 12 = 22

c = 10

Answer 2

Step-by-step explanation: Let C be the number of croissants and P be the number of pain au chocolat that Didier buys. We know that C + P = 22 and 0.85C + 0.95P = 20.

We can solve this system of equations using substitution. First, we solve the first equation for P: P = 22 - C. Then, we substitute this expression for P into the second equation: 0.85C + 0.95(22 - C) = 20. Expanding the expression inside the parentheses and combining like terms, we get: 0.85C + 21.1 - 0.95C = 20.

Then, we can solve for C by moving all the terms to one side of the equation: -0.1C = -1.1. Dividing both sides by -0.1, we get: C = 11.

Substituting this value for C back into the equation P = 22 - C, we get: P = 22 - 11 = 11.

Therefore, Didier buys 11 croissants and 11 pain au chocolat.