Question

What is the volume of 56.0 g of CO2 ast STP

Answer 1

The answer is 28.5 L. Please look at the photo for my work. Hope it helps!

Answer 2

Step-by-step explanation:

STP= 0 degrees

1atm or 101.3 kpa

`pv = nrt`

P=101.3 kpa

v=?

n=mass/molar mass of co2=56/44.01

r=8.314

T=-273 K

`101.3 * v = (56)/(44.01) * 8.314 * 273`

`v = 28.5l`