Question

PLEASE HELPPPPP 50 POINTS!!

(IT SAYS HISTORY BUT ITS MATH)

Edgar measures the temperature of a solution at the beginning of an experiment to be 23 degrees F. He monitors the temperature of the solution every minute for 10 minutes. He records the change in temperature from his previous reading. His data show a decrease of 2 degrees F four times, a decrease of 3 degrees F three times, no temperature change two times, and an increase of 6 degrees F once.

Write an expression that represents the average change in temperature each minute.

Edgar repeats the experiment and finds the average change in temperature each minute is greater in the second trial than in the first trial. What is the average change in temperature each minute in the second trial of the experiment? Show your work.

Answer:

Answer 1

To find the average change in temperature each minute in the first trial of the experiment, we need to add up all of the temperature changes Edgar recorded and divide by the number of temperature changes he recorded. We can represent this with the following expression:(2 degrees F x 4) + (3 degrees F x 3) + (0 degrees F x 2) + (6 degrees F x 1) / 10 temperature changes= 8 degrees F + 9 degrees F + 0 degrees F + 6 degrees F / 10 temperature changes= 23 degrees F / 10 temperature changes= 2.3 degrees F/minuteThis means that the average change in temperature each minute in the first trial of the experiment was 2.3 degrees F.To find the average change in temperature each minute in the second trial of the experiment, we need to determine the average change in temperature each minute in the second trial. This value will be greater than 2.3 degrees F, since the average change in temperature each minute was greater in the second trial than in the first trial. However, we do not have any information about the specific temperature changes Edgar recorded in the second trial, so it is not possible to calculate the average change in temperature each minute in the second trial.