Answer:
Explanation:
SolutionFinal answers are given below.
Back-up Theory and Details of calculations follow at the end.
Part (a)
Estimate of the slope for the least-squares regression line = - 0.0073 Answer 1
InterpretationFor every increase of 1 pound in car’s weight, the fuel efficiency would reduce by 0.0073 mpg. Answer 2
Part (b)
Correlation coefficient, r = - 0.9438 Answer 3
Interpretation An r-value of - 0.9438 indicates that there is a strong inverse linear relation between car’s weight and fuel efficiency.
Negative sign implies that as car’s weight increases, the fuel efficiency would come down.Answer 4
Part (c) The estimated regression equation is: Fuel efficiency = 45.4705 – 0.0073 x car’s weight. Substituting car’s weight = 2684 in the above equation, the estimated fuel efficiency = 25.83.So, residual = 24.5 – 25.84 = - 1.23.
Thus, Residual for a car weighing 2684 pounds and having an average fuel efficiency of 24.5 mpg= - 1.23 Answer 5
Part (d)
Substituting fuel efficiency = 20.2 in the above regression equation, the estimated car’s weight = 3461Estimate of the weight of a car whose fuel efficiency is 20.2 mpg = 3461 pounds Answer 6