Question

A line passing through the points (-8, 13) and (-6, 19)

Answer 1

y = 3x + 37

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = (- 8, 13 ) and (x₂, y₂ ) = (- 6, 19 )

m =
`(19-13)/(-6-(-8))` =
`(6)/(-6+8)` =
`(6)/(2)` = 3 , then

y = 3x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (- 8, 13 ) , then

13 = 3(- 8) + c = -24 + c ( add 24 to both sides )

37 = c

y = 3x + 37 ← equation of line