Question

a 2.55 kg bucket of sand is attached to a 1.31 m long rope and is swung in a vertical circle. at the bottom of the circle the tension in the rope is 30.2 n. what is the speed of the bucket of sand at the bottom of the circle?

Answer 1

Answer: v = 1.64 m/s

Step-by-step explanation:

Fc = (m * v^2)/r

v =
`√((r * Fc) / m)`

v = sqrt((1.31m * (30.2 N - (2.55kg * 9.8 m/s^2))) / 2.55 kg)

v = 1.64 m/s