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Help would be much appreciated!​

Help would be much appreciated!​-example-1

2 Answers

12 votes

Factor the denominator taking 0

  • x²-7x+10=0
  • (x-2)(x-5)=0
  • x={2,5}

Factor numerator

  • x-5=0
  • x=5

x =5 is common so a hole at x=5

User Ian Lunn
by
3.9k points
6 votes

Answer:

  • x = 5

Explanation:

A hole is an input value that makes both numerator and denominator equal to zero.

In other words, same factor in both numerator and denominator.

Let's factorize the denominator:

  • x² - 7x + 10 = x² - 5x - 2x + 10 = x(x - 5) - 2(x - 5) = (x - 2)(x - 5)

We have same factor of x - 5:

  • x - 5 = 0
  • x = 5 is a hole
User Evgen Bodunov
by
4.3k points