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|2х - бу = 1
х- y=1

User Bobulous
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1 Answer

3 votes

Answer:

To solve this system, we need to find the values of x and y that make both equations true at the same time.

Let's start by solving the first equation for y:

|2х - бу = 1

2х - бу = 1

-2х + бу = -1

бу = 1 - 2х

y = (1 - 2х)/б

Now let's substitute this expression for y into the second equation:

x - (1 - 2х)/б = 1

x - 1 + 2х/б = 1

3х/б = 0

x = 0

Substituting this value for x back into the first equation, we get:

y = (1 - 2*0)/б = 1/б

So the solution to the system of equations is x = 0 and y = 1/б.

I hope this helps!

User Kemis
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