Question

I NEED HELP ASAP

A ball is kicked straight up into the air from a height of 3 feet with an initial velocity of 64 ft/s. The height
of the ball in feet after t seconds can be found by the equation h(t)=-16t² +64t+3. What is the maximum
height that the ball reaches? After how many seconds does it reach this height?

Answer 1

Answer: at 4 seconds it will hit the ground. The maximum height is reached at 2 seconds due to the symmetry of the quadratic.

Explanation: