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A seed company planted a floral mosaic of a national flag. The perimeter of the flag is 2,200 ft Determine the flag's width and length if the length is 480 ft greater than the width.

The flag's width is ft. Its length is ft.
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Answer:

the width of the flag is 310 ft and the length is 790 ft.

Explanation:

Let "w" be the width of the flag and "l" be the length of the flag. We can set up the following equation to represent the problem:

2w + 2l = 2200

We know that the length of the flag is 480 ft greater than the width, so we can set up the following equation to represent this relationship:

l = w + 480

We can substitute the second equation into the first equation to solve for the width of the flag:

2w + 2(w + 480) = 2200

This simplifies to:

4w + 960 = 2200

Subtracting 960 from both sides gives us:

4w = 1240

Dividing both sides by 4 gives us:

w = 310

So the width of the flag is 310 ft.

We can use this value to find the length of the flag by substituting it into the equation l = w + 480:

l = 310 + 480

This simplifies to:

l = 790

So the length of the flag is 790 ft.

Therefore, the width of the flag is 310 ft and the length is 790 ft.

User Raya
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