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(a) The quadratic equation (x+2)² +3k-1=0 has two real and distinct roots, where k is a constant. Find the range of values of k.​

User Ihkawiss
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Answer: This means that the range of values of k is k ∈ [-1/3, 1/3].

Step-by-step explanation: The quadratic equation (x+2)² +3k-1=0 can be written as (x+2)² = 1-3k. For the equation to have two real and distinct roots, the expression under the square root must be nonnegative. Therefore, we have the inequality 1-3k ≥ 0. Solving this inequality gives us -1/3 ≤ k ≤ 1/3. This means that the range of values of k is k ∈ [-1/3, 1/3].

User Norbert Bicsi
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