Answer: the number of moles of PbCl2 produced when 16 moles of AlCl3 are consumed is 24 moles.
Explanation: To determine the number of moles of PbCl2 that are produced when 16 moles of AlCl3 are consumed, you will need to balance the chemical equation and use the coefficients in front of each compound to determine the mole ratio.
The balanced chemical equation for the reaction is:
3Pb(NO3)2 + 2AlCl3 → 3PbCl2 + 2Al(NO3)3
Once the equation is balanced, you can use the coefficients in front of each compound to determine the mole ratio. In this case, the coefficient for PbCl2 is 3, and the coefficient for AlCl3 is 2, which means that there is a 3:2 mole ratio between these two compounds. This means that for every 2 moles of AlCl3 that are consumed, 3 moles of PbCl2 are produced.
To calculate the number of moles of PbCl2 produced when 16 moles of AlCl3 are consumed, you can divide the number of moles of AlCl3 by the mole ratio:
moles PbCl2 = 16 moles AlCl3 / (3 moles PbCl2 / 2 moles AlCl3)
= 16 moles AlCl3 / (3/2)
= 24 moles PbCl2