a)
Explanation:
we only need to look at the point, where y = 0.
that is clearly at x = 3.
which function gives y = 0 as result, when x = 3 ?
only a)
y =
![\sqrt[3]{3 - 3}](https://img.qammunity.org/2023/formulas/mathematics/high-school/hszk2obihyg99pn9aj00azqmbm4gqxln07.png)
the cubic root of 0 is 0.
as 3 is not equal to the cubic root of 3, b), c) and e) are out.
and d) is
![y = \sqrt[3]{3 + 3}](https://img.qammunity.org/2023/formulas/mathematics/high-school/jryvf1hjm6i8r7if5ilsop4rxlxbfeanu5.png)
the cubic root of 6 is NOT 0.
so, only a) is the only right answer.