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Use the equation below to answer the following question. How many grams of potassium chloride (KCl) are produced if 25 g of potassium chlorate (KClO3) decompose?

2KClO3 → 2KCl + 3O2

1 Answer

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Answer:

15 grams.

Step-by-step explanation:

Molar mass of KClO3 = (39.10+35.45+3(16.00)) g/mol = 122.55 g/mol. Why? Because the molar mass of a compound is the sum of the molar masses of its constituents. There is 1 K atom, 1 Cl atom, and 3 O atoms in KClO3.

We can determine the mols of KClO3 given its mass and molar mass. How? Using the factor-label method (cancelling units out):

25 g * 1mol/122.55g = 0.203998368 mol.

We must now use mol ratios to determine the amount of potassium chloride (in mols) produced:

n of KCl = 0.203998368 mol(KClO3) * (2 mol KCl)/(2 mol KClO3) = 0.203998368 mol.

Molar mass of KCl = (39.10 + 35.45) g/mol = 74.55 g/mol.

From here, we can find the mass of KCl using the same logic discussed above:

m of KCl = 0.203998368 mol * 74.55 g/mol = 15.20807833 g = 15 g (rounded in accord with significant figures)

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