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If x^2 + y^2 = 289, find the value of dy/dt at (8,15)

If x^2 + y^2 = 289, find the value of dy/dt at (8,15)-example-1
User M A Russel
by
6.3k points

1 Answer

1 vote

Answer: a)

Explanation:

To find
(dy)/(dx), we will have to use implicit differentiation, and because the base is
dx, we will take the deriviative of both sides with respect to
x.

To derive
y with respect to
x, just derive the term with respect to y then multiply the term with
(dy)/(dx).

So
(d)/(dx) x^(2) is just
2x,
(d)/(dx) y^(2) is
2y (dy)/(dx), and
(d)/(dx) 289 is 0. Now substitue each term with it's deriviative.


2x + 2y (dy)/(dx) = 0

Now, just solve for
(dy)/(dx) when
x is 8 and
y is 15


2(8) + 2(15)(dy)/(dx) = 0


16 + 30(dy)/(dx) = 0


(dy)/(dx) = (-16)/(30) = (-8)/(15)

So the answer is choice a)

User Resander
by
4.7k points