Question

Given BC over AC congruent to EF over EG
Prove FG=10

Answer 1

Proof:

Let's start of by solving for the length of AC, which is just the sum of lengths AB and BC, which is 10 + 3 = 13 units.

Because of our second given, AC ≅ EG, we know that EG is also 13 units in length. Also, from our first given, BC ≅ EF, we know that EF is 3 units.

We also know that the length of EG is the sum of lengths EF and FG so we can write the equation

EG = EF + FG

13 = 3 + FG

FG = 10 meaning FG is 10 units