Question: A negative 6 mC charge enters a region of 45 T magnetic field that is directed up. If the charge is moving toward the south with a speed of 400 m/s. determine the magnitude and direction of the force
Answer:
Magitude of F = 108 N
Direction: Perpendicular to the plane containing v and B.
Step-by-step explanation:
From the question,
Since the velocity of the charge(v), is parallel to the field(B).
Therefore, We apply
F = qvB..................Equation 1
Where F = Force, B = magnetic field, v = velocity, q = Charge.
Given: q = 6 mC = 0.006 C, v = 400 m/s, B = 45 T
Substitute these values into equation 1
F = 0.006×400×45
F = 108 N.
The direction of the force is always perpendicular to the plane containing v and B.