Question

The length of a rectangle is 2m longer than its width. If the perimeter of the rectangle is , 60 find its length and width.

Answer 1

Let the width of the rectangle be w.

Then the length of the rectangle is w+2.

The perimeter of the rectangle is the sum of all its sides, so it is 2(w) + 2(w+2) = 60.

Expanding the parentheses and combining like terms, we get:

2w + 2w + 4 = 60

4w + 4 = 60

4w = 56

w = 14

The width of the rectangle is 14.

The length of the rectangle is 14+2 = 16.

Therefore, the length of the rectangle is 16 and the width is 14.

CORRECT ME IF I'M WRONG