Answer:
22
Explanation:
Let's say the 4 consecutive integers are a, b, c, and d
a=b-2 ==> Consecutive even numbers have a difference of 2: Ex. (4-2=2)
b=c-2
c=d-2
a+b+c+d=100
Solve for a:
a=b-2 ==> add 2 on both sides
a+2=b
a+(a+2)+c+d=100 ==> substitute a+2 for b
a+2=c-2 ==> b=c-2 and a+2=b, so a+2=c-2
a+2+2=c-2+2 ==> add 2 on both sides
a+4=c
a+(a+2)+(a+4)+d=100 ==> substitute a+4 for c
a+4=d-2 ==> c=d-2 and a+4=c, so a+4=d-2
a+4+2=d-2+2 ==> add 2 on both sides
a+6=d
a+(a+2)+(a+4)+(a+6)=100 ==> substitute a+6 for d
a+a+2+a+4+a+6=100 ==> solve for a
a+a+a+a+2+4+6=100
4a+12=100 ==> simplify
4a+12-12=100-12 ==> isolate a
4a=88 ==> simplify
a=88/4
a=22