Question

100.0 mL of a 0.630 M solution of KBr is diluted to 500.0 mL. What is

the new concentration of the solution?

Answer 1

C2= 0.126M

Step-by-step explanation:

C1*V1=C2*V2

C1= 0.630M

C2=?

V1= 100.0ML

V2= 500.0ML

0.630*100 = C2*500

C2= 0.630*100÷500

C2= 63÷500

C2= 0.126M