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an object moving with an initial velocity of 40 m/s takes 2.0 seconds to slow to a speed of 10 m/s. what is the magnitude of the acceleration of the object?

User Oded Peer
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1 Answer

5 votes

Answer: a = -15 m/s^2

Step-by-step explanation:

a = Δv/Δt

a = (10 m/s - 40 m/s)/(2.0 s)

a = -15 m/s^2

User John Cordeiro
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