Answer: The minimum frequency of light required to ionize one electron from one atom of sodium is approximately 119,637.9 megahertz (MHz).
Explanation: The ionization energy of an atom is the minimum amount of energy required to remove an electron from the atom. In the case of sodium, the ionization energy at position 24 is 496 kJ/mol, which means that it takes 496 kJ of energy to remove one mole of electrons from one mole of sodium atoms.
The frequency of light is related to its energy through the equation E = hf, where E is the energy, h is the Planck constant, and f is the frequency. To determine the minimum frequency of light required to ionize one electron from one atom of sodium, you can rearrange this equation to solve for f:
f = E / h
Substituting the values for E and h, and converting the units to the appropriate units for frequency (Hz), you can calculate the minimum frequency of light required to ionize one electron from one atom of sodium:
f = (496 kJ/mol) / (4.135667662 x 10^-15 eV*s)
= 119637.9 MHz
This means that the minimum frequency of light required to ionize one electron from one atom of sodium is approximately 119,637.9 megahertz (MHz).
Keep in mind that this is the minimum frequency required to ionize one electron from one atom of sodium, and that higher frequencies may be required to ionize multiple electrons or to ionize atoms with higher ionization energies.