Question

Noah has $300 to spend this school year. He will be purchasing lunches at the rate of $2.25 each day, d, and buying a pair of $120 shoes. Which inequality reveals how many days Noah can afford to buy lunch?

Answer 1

Explanation:

of the shoes from the total amount of money he has, and then divide the remaining amount by the cost of each lunch. This can be represented by the inequality:

2.25d < 300 - 120

This inequality states that the cost of the lunches, at $2.25 per day, must be less than the remaining amount of money that Noah has after purchasing the shoes.

To solve this inequality, you can begin by substituting the value of 300 - 120 into the inequality, to get:

2.25d < 180

Next, you can divide both sides of the inequality by 2.25 to solve for d:

d < 80

This means that Noah can afford to buy lunch for fewer than 80 days. To find the maximum number of days he can afford to buy lunch, you can round down to the nearest whole number, which is 79 days.

Therefore, the inequality that represents the number of days that Noah can afford to buy lunch is d < 79.

Answer 2

Answer: he can buy lunch for 80 days (d ≤ 80)

Explanation:

letd=number of days purchasing lunch

2.25d + 120 ≤ 300

you want to start by subtracting 120 from both sides.

this gives you 2.25d ≤ 180

then you divide by 2.25 on both sides

d ≤ 80