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A 700 kg race car makes one lap around a track. It has a velocity of 20 m/s with a centripetal force of 5,600 N. What is the radius of the track?

A speed skater goes around a turn with a 25 m radius. The skater has a velocity of 15 m/s and experiences a centripetal force of 720 N. What is the mass of the skater?

A 900-kg car moving at 5 m/s takes a turn around a circle with a radius of 30 m. Determine the net force acting upon the car.

An 800 kg race car makes one lap around a track. It has a velocity of 40 m/s with a centripetal force of 16,000 N. What is the radius of the track?

User Nightire
by
4.6k points

1 Answer

4 votes

Answer:

Question 1. 50 m

Question 2. 80 kg

Question 3. 750 N

Question 4. 80 m

Step-by-step explanation:

Here are some equations that we might have to use.


F_(Cnet) =m*a_c\\F_(Cnet) =(m*v^2)/(r)\\a_c=(v^2)/(r)\\a_c=(F_(Cnet) )/(m)\\m=(F_(Cnet) )/(a_c)\\m=(F_(Cnet) *r)/(v^2) \\r=(m*v^2)/(F_(Cnet) )\\r=(v^2)/(a_c)

Question 1

We are given


m=700\\v=20\\F_(Cnet)=5600

We will use
r=(m*v^2)/(F_(Cnet) )


r=(700*20^2)/(5600)


r=50

Question 2

We are given


r=25\\v=15\\F_(Cnet) =720

We will use
m=(F_(Cnet) *r)/(v^2)


m=(720*25)/(15^2)


m=80

Question 3

We are given


m=900\\v=5\\r=30

We will use
F_(Cnet) =(m*v^2)/(r)


F_(Cnet) =(900*5^2)/(30)


F_(Cnet) =750

Question 4

We are given


m=800\\v=40\\F_(Cnet)=16000

We will use
r=(m*v^2)/(F_(Cnet) )


r=(800*40^2)/(16000)


r=80

Hopefully this helps! A rating/review would be much appreciated! :)

User Bharat Kumar
by
5.0k points