Question

A student slides a 0.45 kg textbook across a table. What will be the kinetic energy of the textbook

if its speed is 0.20 m/s?

Answer 1

Below

Step-by-step explanation:

Kinetic Energy = 1/2 * m * v^2

= 1/2 * .45 * .2^2 = .009 J

Answer 2

Important Formulas:

`KE=.5mv^2`

Kinetic Energy(measured in joules) = .5 * mass(measured in kg) * velocity(measured in m/s)^2

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Given:

`m=0.45kg`

`v=0.20m/s`

`KE=?`

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`KE=.5mv^2`

`KE=.5(0.45)(0.20)^2`

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`\fbox{KE = 0.009J}`