Question

D. 4225 N

18. Someone is pulling 10kg brick upward with a rope. If the force of tension on the rope is
120N, what is the acceleration? (hint: draw a FBD. The rope has to overcome gravity
before the brick accelerates!) F, = mg & Fnet = ma
a. 10 m/s²
b. 2.2 m/s²
c. 12 m/s²
d. 1200 m/s²

Answer 1

Option B. 2.2 m/s^2

Step-by-step explanation:

The tension in the rope can be defined as

`T=mg+ma`

Lets solve for
`a`.

Subtract
`mg` from both sides of the equation.

`ma=T-mg`

Divide each term in
`ma=T-mg` by
`m` and simplify.

`(ma)/(m)=(T)/(m)+ (-mg)/(m)`

`a=(T)/(m)-g`

Substituting in out numbers gives us

`a=(120)/(10)-9.81`

`a=2.19`