229k views
3 votes
Differentiate y=2-3x/(3-4x)^2​

1 Answer

3 votes

Answer:

Hope this helps ;) don't forget to rate this answer !

Explanation:

To differentiate y = 2 - 3x/(3 - 4x)^2, we can use the quotient rule for differentiation.

The quotient rule states that if f(x) = g(x)/h(x), then the derivative of f(x) is given by:

f'(x) = (g'(x)h(x) - g(x)h'(x)) / h(x)^2

In this case, we can set f(x) = 2 - 3x/(3 - 4x)^2, g(x) = 2, and h(x) = (3 - 4x)^2.

Substituting these values into the formula for the derivative of a quotient, we get:

f'(x) = (2*(3 - 4x)^2 - (2 - 3x)*(-8x)) / (3 - 4x)^4

Simplifying this expression gives:

f'(x) = (-24x^2 + 24x + 6) / (3 - 4x)^3

This is the derivative of y = 2 - 3x/(3 - 4x)^2.

User Vlad Patryshev
by
3.3k points