Question

Help me with #54 and #55?please?

Answer 1

Answer: In the step by step explanation

Explanation:

Q54

This question is very unclear but I will try my best to answer.

For f(x) to be zero, one of it's factors must be zero, so let's start with 5x - 2 = 0 which we can solve to get x =
`(2)/(5)`. For
`5x^(2) - 4` = 0, we can do the same as last time to get x = ±
`(2)/(√(5))` and fot
`3x^(2)-2=0`, we can get x = ±
`\sqrt{(2)/(3) }`

Q55

Using our beloved right angled triangle, SOH-CAH-TOA, and the fact that we are given that the tangent is positive and sine is negative, we are given that the length of the side opposing the angle is 1, the length of the side adjacent to the angle is 5, meaning that the hypotenuse is
`\sqrt{1^(2) +5^(2) }` =
`√(26)` and because they told us that tan is positive and sin is negative, we are in Quadrant 3.

We know that the cotangent is the cosine divided by the sine or A/O which is 5/1 or 5

The cosecant is found by taking 1 divided by the sine which is 1/(O/H) or H/O which is
`(√(26))/(1)` or
`√(26)`