Answer:
1- To find the time it takes for the rocket to hit the ground, we need to solve the equation h = 0. Substituting 0 for h and solving for t, we get:
0 = -4.9t^2 + 33.6t + 4.9
-4.9t^2 + 33.6t + 4.9 = 0
Using the quadratic formula, we get:
t = (-33.6 +/- sqrt(33.6^2 - 4(-4.9)(4.9))) / (2(-4.9))
t = (-33.6 +/- sqrt(1124.96)) / -9.8
t = (-33.6 +/- sqrt(1132.56)) / -9.8
t = (-33.6 +/- 33.6) / -9.8
t = (-67.2) / -9.8
t = 6.939
The rocket will hit the ground after approximately 6.939 seconds.
2- Let w be the width of the rectangle and l be the length. We are given that l = 5w - 7 and that the area of the rectangle is 24. We can set up the equation lw = 24 and substitute the expression for l:
(5w - 7)w = 24
5w^2 - 7w = 24
5w^2 - 7w - 24 = 0
Using the quadratic formula, we get:
w = (7 +/- sqrt(49 - 4(5)(-24))) / (2(5))
w = (7 +/- sqrt(49 - -120)) / 10
w = (7 +/- sqrt(169)) / 10
w = (7 +/- 13) / 10
w = 20/10 or w = -6/10
w = 2 or w = -0.6
Since the width cannot be negative, the width of the rectangle is 2 cm. The length is then 5w - 7 = 5(2) - 7 = 3 cm.
3- Jeff can build the wall in 10 - 1 = 9 hours. Kirk can build the wall in 10 hours. The combined time it takes for Jeff and Kirk to build the wall is 9 + 10 = 19 hours. The total time it takes for Kirk to build the wall is 75 / (1/10) = 750 minutes. 750 minutes is equivalent to 750/60 = 12.5 hours. Kirk builds the wall in 12.5 - 10 = 2.5 hours. Kirk builds the wall in 2.5 hours, or 2.5 * 60 = 150 minutes. Kirk will take approximately 150 minutes to build the wall by himself.
4- The student's average score so far is (87 + 85 + 91) / 3 = 263 / 3 = 87.67. To have an average of at least 90, the student needs to score at least 90 * 4 - 263 = 360 - 263 = 97. The student must score at least 97% on the next exam.