To solve this system of equations by substitution, we can start by solving one of the equations for one of the variables. Let's solve the first equation for x:
8x = 5 - 3y
x = (5 - 3y) / 8
Now, we can substitute this expression for x into the second equation to solve for y:
3((5 - 3y) / 8) = 8 - 2y
15 - 9y = 8 - 2y
-y = -7
y = 7
Now that we know the value of y, we can substitute it back into either of the original equations to solve for x. Let's use the first equation:
8x = 5 - 3(7)
8x = 5 - 21
8x = -16
x = -2
Therefore, the solution to the system of equations is x = -2 and y = 7.
To solve this system of equations by substitution, we can start by solving one of the equations for one of the variables. Let's solve the second equation for a:
a = (5a - b) / 5
a = 5a / 5 - b / 5
a = a - b / 5
5a = a - b
4a = -b
b = -4a
Now, we can substitute this expression for b into the first equation to solve for a:
a = 4 + (-4a)
a = 4 - 4a
5a = 4
a = 4/5
Now that we know the value of a, we can substitute it back into the second equation to solve for b:
b = -4(4/5)
b = -16/5
b = -3.2
Therefore, the solution to the system of equations is a = 4/5 and b = -3.2.