The equation of the line passing through the points (2,5) and (1,1) is 4x - y = 3 in standard form.
The standard form of the equation of a line is given by:
Ax + By = C
To find the equation of the line passing through the points (2,5) and (1,1), we can use the point-slope form of the equation:
(y - y₁)/(x - x₁) = m
where m is the slope of the line and (x₁, y₁) is a point on the line. Let's calculate the slope first:
m = (y₂ - y₁)/(x₂ - x₁)
Using the points (2,5) and (1,1):
m = (1 - 5)/(1 - 2) = (-4)/(-1) = 4
Now that we have the slope (m = 4), we can use one of the given points to write the point-slope form. Let's use the point (2,5):
(y - 5)/(x - 2) = 4
Multiply both sides by (x - 2) to get rid of the fraction:
y - 5 = 4(x - 2)
Distribute 4 on the right side:
y - 5 = 4x - 8
Add 5 to both sides:
y = 4x - 3
Now, let's write this equation in standard form:
4x - y = 3
So, the equation of the line in standard form is 4x - y = 3.