Question

the current in a single-loop circuit with one resistance r is 9:50 ma. when an additional resistance of 660 is inserted in series with r, the current drops to 3:50 ma. what is r?

Answer 1

r = 385 Ω

Step-by-step explanation:

OHM LAW : V = I x R

In the first circuit

V = I₁ x r = 9.5 x r mv

In the second circuit with the same V

V = I₂ x ( r +660) = 3.5 x ( r + 660)

9,5r = = 3.5 ( r + 660)

9.5 r = 3.5r + 2310

6r = 2310

r = 2310/6

r = 385 Ω