Question

12) What height must a 2.5 kg object be dropped from to have
2000 J of potential energy?

Answer 1

81.6m

Step-by-step explanation:

The formula for potential energy is PE=mgh, where PE is potential energy, m is mass, g is acceleration due to gravity (9.81m/s)and h is height.

Sub in our values for mass and potential energy and the value for acceleration due to gravity to find the height:

PE=mgh

2000=(2.5)(9.81)h

h=2000/24.5=81.632653m

Answer 2

81.6 m

Step-by-step explanation:

PE = mgh

h = (PE)/(mg) = (2000 J) / ((2.5 kg)(9.8 m/s²)) = 81.6 m