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What value of c satisfies the conclusion of the mean value theorem for f(x) = 10x over the interval [0, 2]?

User SeedyROM
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Answer:

the value of c that satisfies the conclusion of the mean value theorem is c = 5

Explanation:

The mean value theorem states that if a function f is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), then there exists a number c in the interval (a, b) such that:

f'(c) = (f(b) - f(a)) / (b - a)

In this case, we are given the function f(x) = 10x, and the interval [a, b] is [0, 2]. Plugging these values into the equation above, we get:

f'(c) = (f(2) - f(0)) / (2 - 0)

= (20 - 0) / 2

= 10 / 2

= 5

Therefore, the value of c that satisfies the conclusion of the mean value theorem is c = 5.

UPDATED: To find the value of c that satisfies the conclusion of the mean value theorem for the function f(x) = 10^x over the interval [0, 2], you can use the equation:

f'(c) = (f(b) - f(a)) / (b - a)

In this case, a = 0, b = 2, and f(x) = 10^x, so we can plug these values into the equation to find the value of c:

f'(c) = (f(2) - f(0)) / (2 - 0)

= (10^2 - 10^0) / 2

= 100 / 2

= 50

Therefore, the value of c that satisfies the conclusion of the mean value theorem is c = 50.

I hope this helps clarify things. If you have any further questions, please don't hesitate to ask.

User EddyLee
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