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A circular fair ride with a radius of 9.0 m causes participants to feel a centripetal acceleration of 54 m/s2. At what speed must the ride rotate to create this acceleration?

A.6.0 m/s
B.22 m/s
C.320 m/s
D.490 m/s

User Oberon
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Answer:B.22 m/s

Step-by-step explanation:

The centripetal acceleration of an object moving in a circular path is given by the following formula:

a = v²/r

Where a is the centripetal acceleration, v is the speed of the object, and r is the radius of the circular path.

We are given that the centripetal acceleration is 54 m/s2 and the radius of the circular path is 9.0 m. We want to solve for the speed v.

Substituting the given values into the formula and solving for v, we get:

v = √(a * r)

Substituting the given values, we get:

v = √(54 m/s2 * 9.0 m)

This simplifies to:

v = √(486 m²/s²)

Which simplifies to:

v = 22 m/s

Therefore, the speed at which the ride must rotate to create a centripetal acceleration of 54 m/s2 is 22 m/s.

User Dinosaur
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