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22. A force of 5.0 N moves a 6.0 kg object along a rough floor at a constant speed of 2.5 m/s.

(a) How much work is done in 25 s?
(b) What power is being used?
(c) What force of friction is acting on the object?

User MrMaavin
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1 Answer

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Step-by-step explanation:

a) Power is being used will be 12.5 Watts.

b) Force of friction is acting on the object will be 5 Newton.

What is the friction force?

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

Mathematically it is defined as the product of the coefficient of friction and normal reaction.

The given data in the problem is;

m is the mass of object =6.0 kg

u is the speed =2.5 m/s

a) Power is being used will be 12.5 Watts.

The distance traveled by the object is;

\begin{gathered}\rm d = v \times t \\\\ \rm d = 2.5 \times 25 \\\\ \rm d = 62.5 m\end{gathered}

d=v×t

d=2.5×25

d=62.5m

The work done is the product of force and displacement;

\begin{gathered}\rm W = F \times d \\\\ \rm W = 5 \times 62.5 \\\\ \rm W = 312.5 \ J\end{gathered}

W=F×d

W=5×62.5

W=312.5 J

The power is the ratio of work done to the time;

\begin{gathered}\rm P= \frac{W}{t} \\\\ \rm P= \frac{312.5 }{25 } \\\\\ \rm P=12.5 \ Watt\end{gathered}

P=

t

W

P=

25

312.5

P=12.5 Watt

Hence Power is being used will be 12.5 Watts.

b) Force of friction is acting on the object will be 5 Newton.

If the all unbalanced force is zero the net force is equal to the force of friction;

The force of friction= Net force

Force of friction= 5 Newton.

Hence the force of friction is acting on the object will be 5 Newton.

User Simon Park
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