124k views
5 votes
If 1 is a root of the equation
5x^{2} +kx -21 =0.
find the other root

1 Answer

1 vote

Answer:

x = - 4.2

Explanation:

5 + k - 21 = 0

k - 16 = 0

k = 16


5x² + 16x - 21 = 0


discriminant = 256 - 4( 5 · -21)

256 - 4 (-105)

256 + 420

676


x = (- 16 + 26)/10

x = 10/10

x = 1


x = (-16-26)/10

x = -42/10

x = -4.2

User Userx
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories